A careful observer will notice that in the previous sections, we only looked at a handful of domain values to essentially make a guess as to where the function is headed. Consider, for example, our friend \(sin(x)/x\text{.}\) Look at the table we made at the beginning of the first section. We stopped looking once we let \(x\) get down to \(0.001\text{.}\) But what about even closer? Like \(x=0.0003\) or \(x=0.0000000162\) or \(x=0.0000000000004\text{?}\) Maybe waaaay down there \(sin(x)/x\) starts getting wonky. Maybe. So, right now weβre just guessing that \(\displaystyle \lim_{x\to 0^{+}}(sin(x)/x)=1\text{.}\) Educated guessing ... yes. But still just guessing. Weβd like to start moving past just guessing. We start doing that in this section. We start by looking at a couple of functions whose limits are not in question.
First, consider a constant function like \(f(x)=5\text{.}\) No matter what you put in for \(x\text{,}\) it gives us \(5\text{.}\) So, thereβs no question what itβs approaching regardless of where we let \(x\) go. Itβs always giving \(5\text{.}\) So, we have ...
Secondly, consider the function \(f(x)=x\text{.}\) Well, this function just does whatever \(x\) does. So, where \(x\) goes, so does \(f(x)=x\text{.}\) Thus, we have ...
If \(\displaystyle \lim_{x\to a}f(x)=l\) and \(\displaystyle \lim_{x\to a}g(x)=k\) and \(r\) and \(s\) are any two numbers and the right hand side of the following equalities are defined, Then \(\displaystyle \lim_{x\to a}(rf(x)+sg(x))=rl+sk\text{,}\)\(\displaystyle \lim_{x\to a}(f(x)g(x))=lk\text{,}\) and \(\displaystyle \lim_{x\to a}(f(x)/g(x))=l/k\text{.}\)
It is also the case that if all of the \(\displaystyle \lim_{x\to a}\) are replaced with either \(\displaystyle \lim_{x\to a^{+}}\) or \(\displaystyle \lim_{x\to a^{-}}\text{,}\) then the theorem TheoremΒ 1.3.3 is still correct.
Often, people cite this basic properties theorem by saying, "the limit of a sum is the sum of the limits, the limit of a product is the product of the limits, and the limit of a ratio is the ratio of the limits".
Please note that, from the conditions of the theorem, if the right hand side of any of the equalities in this theorem can not be computed, then the theorem is not making a statement (i.e. isnβt valid, isnβt a thing). For example, if \(k=0\) in the theorem, then we certainly are not claiming that \(\displaystyle \lim_{x\to a}(f(x)/g(x))=l/k\) since the right hand side of this equality is \(l/0\) which isnβt even a thing to claim something is.
Use TheoremΒ 1.3.3 to compute \(\displaystyle \lim_{x\to 2}(x^2)\text{,}\)\(\displaystyle \lim_{x\to -1}(x^2+3x)\text{,}\) and \(\displaystyle \lim_{x\to 0}(x^2+3x)/(x+2)\text{.}\)